Please note that the steps show rounded numbers, but that the final answers to the problems are calculated without rounding.
| Problem | Part | Solution |
|---|---|---|
| 1 | - | The standard deviation is a measure of how spread out the data are. A larger standard deviation indicates that data are more spread out and less consistent than data that have a smaller standard deviation. |
| 2 | - | Box Plot C |
| 3 | - | a. Right Skewed |
| 4 | - | $46,172 |
| 5 | - | $18,882 |
| 6 | - | $105,987 |
| 7 | - | c. have a longer whisker on the left side |
| 8 | - | c. The percentage of data is the same for both. |
| 9 | - | This is just a rough estimate, but somewhere between 190 and 200 |
| 10 | - | Right-skewed |
| 11 | - | 4 hours |
| 12 | - | 14 hours |
| 13 | - | 2 and 4 hours |
| 14 | - | There is not enough information to answer this question. We need the original data to make this determination. |
| 15 | A | Uniform = b |
| 15 | B | Bell-shaped = d |
| 15 | C | Right-skewed = a |
| 15 | D | Left-skewed = e |
| 15 | E | Symmetric, but not bell-shaped or uniform = c |
| 16 | - | The mean |
| 17 | - | \(28.5 \text{ nCi/L}\) |
| 18 | - | \(-23.9 \text{ nCi/L}\) |
| 19 | - | \(1777.5 \text{ nCi/L}\) |
| 20 | - | \(904.1 (\text{ nCi/L})^2\) |
| 21 | - | \(30.1 \text{ nCi/L}\) |
| 22 | - | c. {0, 0, 10, 10} |
| 23 | - | b. The standard deviation will decrease. |